ehdr->e_shentshize and ehdr->e_shnum are both 16-bit unsigned integers
and so their types get implicitly promoted to signed int automatically
during the multiplication, they must be explicitly cast into a larger
unsigned type, otherwise if the signed product is large enough the
value is sign extended resulting in incorrect values.
Signed-off-by: Sunday Clement <Sunday.Clement@amd.com>
Sunday Clement
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